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55 lines
1.3 KiB
Bash
Executable File
55 lines
1.3 KiB
Bash
Executable File
#!/bin/sh
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# Ensure that hard-linked files are counted (and listed) only once.
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# Likewise for excluded directories.
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# Ensure that hard links _are_ listed twice when using --count-links.
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if test "$VERBOSE" = yes; then
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set -x
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du --version
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fi
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. $srcdir/../envvar-check
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. $srcdir/../lang-default
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pwd=`pwd`
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t0=`echo "$0"|sed 's,.*/,,'`.tmp; tmp=$t0/$$
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trap 'status=$?; cd $pwd; chmod -R u+rwx $t0; rm -rf $t0 && exit $status' 0
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trap '(exit $?); exit $?' 1 2 13 15
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framework_failure=0
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mkdir -p $tmp || framework_failure=1
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cd $tmp || framework_failure=1
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mkdir -p dir/sub
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( cd dir && { echo non-empty > f1; ln f1 f2; echo non-empty > sub/F; } )
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if test $framework_failure = 1; then
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echo "$0: failure in testing framework" 1>&2
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(exit 1); exit 1
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fi
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fail=0
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# Note that for this first test, we transform f1 or f2
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# (whichever name we find first) to f_. That is necessary because,
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# depending on the type of file system, du could encounter either of those
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# two hard-linked files first, thus listing that one and not the other.
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du -a --exclude=sub dir \
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| sed 's/^[0-9][0-9]* //' | sed 's/f[12]/f_/' > out || fail=1
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echo === >> out
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du -a --exclude=sub --count-links dir \
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| sed 's/^[0-9][0-9]* //' | sort -r >> out || fail=1
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cat <<\EOF > exp
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dir/f_
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dir
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===
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dir/f2
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dir/f1
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dir
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EOF
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cmp out exp || fail=1
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test $fail = 1 && diff -u out exp 2> /dev/null
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(exit $fail); exit $fail
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