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coreutils/tests/chgrp/deref
Jim Meyering ae2b0d2ddc tests: more automated quote adjustment
Relax initial regexp to match more instances, but add a
filter to avoid some invalid conversions.  Run this:

git grep -l "\`[^']*'" tests | xargs perl -pi -e '$q=q"'\''";' \
  -e '$q="$q\\$q$q"; /(= ?\`|\`expr|\`echo|\Q$q\E)/ and next;' \
  -e ' s/\`([^'\''"]*?'\'')/'\''$1/g'
The last disjunct in the above (...) filter is to exempt
any line that contains this string: '\''
With quoting like that, converting a ` to ' is likely to cause trouble,
so we'll handle those manually.  Here are three examples where
the exemption is required:

  *': `link-to-dir/'\'': hard link not allowed for directory'*) ;;
  printf 'creating file `%s'\''\n' $f
  'mv: inter-device move failed: `%s'\'' to `%s'\'';'\
2012-01-09 21:50:08 +01:00

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#!/bin/sh
# see if chgrp can change the group of a symlink
# Copyright (C) 2000, 2004-2012 Free Software Foundation, Inc.
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
. "${srcdir=.}/init.sh"; path_prepend_ ../src
print_ver_ chgrp
require_membership_in_two_groups_
set _ $groups; shift
g1=$1
g2=$2
touch f
ln -s f symlink
chgrp -h $g2 symlink 2> /dev/null
set _ `ls -ln symlink`
g=$5
test "$g" = $g2 ||
skip_ "your system doesn't support changing the owner or group" \
"of a symbolic link."
chgrp $g1 f
set _ `ls -ln f`; g=$5; test "$g" = $g1 || fail=1
chgrp -h $g2 symlink || fail=1
set _ `ls -ln f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -ln symlink`; g=$5; test "$g" = $g2 || fail=1
# This should not change the group of f.
chgrp -h $g2 symlink || fail=1
set _ `ls -ln f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -ln symlink`; g=$5; test "$g" = $g2 || fail=1
chgrp $g2 f
set _ `ls -ln f`; g=$5; test "$g" = $g2 || fail=1
# This *should* change the group of f.
# Though note that the diagnostic you'd get with -c is misleading in that
# it says the 'group of 'symlink'' has been changed.
chgrp --dereference $g1 symlink
set _ `ls -ln f`; g=$5; test "$g" = $g1 || fail=1
set _ `ls -ln symlink`; g=$5; test "$g" = $g2 || fail=1
Exit $fail