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expr: don't interpret argv[0] as an operand

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* src/expr.c (main): Given a first argument like -22 (negative, with
two or more digits), expr would decrement optind to 0 and then attempt
to evaluate argv[0].
This commit is contained in:
Jim Meyering
2008-10-15 09:19:29 +02:00
parent 555c219d9e
commit 514b7fbc00
1 changed files with 4 additions and 1 deletions
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5
src/expr.c
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@@ -261,6 +261,7 @@ main (int argc, char **argv)
{
VALUE *v;
int c;
int saved_optind;
initialize_main (&argc, &argv);
set_program_name (argv[0]);
@@ -273,6 +274,7 @@ main (int argc, char **argv)
/* The argument -0 should not result in an error message. */
opterr = 0;
saved_optind = 1;
while ((c = getopt_long (argc, argv, "+", long_options, NULL)) != -1)
{
@@ -282,7 +284,7 @@ main (int argc, char **argv)
*/
if ('?' == c)
{
--optind;
optind = saved_optind;
break;
}
else
@@ -305,6 +307,7 @@ main (int argc, char **argv)
case_GETOPT_VERSION_CHAR (PROGRAM_NAME, AUTHORS);
}
saved_optind = optind;
}
if (argc <= optind)